Please help with these 6 questions 22. What is the coefficient in front of oxyge

Question

Please help with these 6 questions

22. What is the coefficient in front of oxygen in the following balanced equation b. 5 C. 13 d. 26 23. Which of the following is the precipitate formed in a reaction between silver nitrate and sodium chloride a. Silver chloride b. Sodium nitrate c. Sodium chloride d. Silver nitrate e. None of the above 24. In the following reaction, which species is oxidized a. Zn b. Cu c. Zn d. Cu e. None of the above 25. What is the molar mass of glucose CsH120? a. 29 b. 44 c. 72 d. 180 e. 210 26. How many grams of water are produced when 15 grams of oxygen are combusted in the following reaction a. 15 b. 34 d. 13 e. 26 27. How many grams of aluminum are in 1.25 x 10" molecules of aluminum? a. 2 b. 27 C. 56 d. 7.5 x 101 e. 2.0 x 10

Explanation / Answer

22) The coefficient in front of oxygen is 13. option C is correct.

Explanation: the balanced equation is

2 C4H10 + 13 O2 ------> 8 CO2 + 10 H2O

23) The precipitate formed is AgCl, silver chloride.option A is correct

Explanation: AgNO3 + NaCl -----> AgCl + NaNO3

24) Zn is oxidized. option A is correct

Explanation: conversion of oxidation state from 0 to +2 is called oxidation.

25) The molar mass of glucose is 180. option D is correct

Explanation: molar mass of glucose = 6(molar mass of C) + 12(molar mass of H) + 6(molar mass of oxygen)

molar mass of glucose = 6(12) + 12(1) + 6(16) = 72 + 12 + 96 = 180

26) number of moles of oxygen = 15 g / 32.0 g/mol = 0.469 mol

from the balanced equation we can say that

1 mole of oxygen produces 2 mole of H2O so

0.469 mol of oxygen will produce 0.938 mole of H2O

mass of 1 mole of H2O = 18.016 g

so the mass of 0.938 mole of H2O = 17 g

Therefore, the mass of H2O produced would be 17 g

option C is correct

27) 6.023*10^23 molecules of aluminum = 1 mole

1.25*10^24 molecules of aluminum= 2.08 mol

mass of 1 mole of Al = 27.0 g

so the mass of 2.08 mole of Al = 56 g

Therefore, the mass of Al would be 56 g

option C is correct

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