Calcium cyanamide, CaCN2, reacts with water to form calcium carbonate and ammoni

Question

Calcium cyanamide, CaCN2, reacts with water to form calcium carbonate and ammonia; CaCN2(s)+3H2O(l)-->CaCO3(s)+2NH3(g). a) How many grams of water are needed to react with 75.0 g of CaCN2? b) How many grams of NH3 are produced from 5.24 g of CaCN2? c) How many grams of CaCO3 form if 155 g of water reacts?

Explanation / Answer

CaCN2(s)+3H2O(l)=========>CaCO3(s)+2NH3(g) a) How many grams of water are needed to react with 75.0 g of CaCN2? 75.0 g CaCN2 (1 mol CaCN2/ 80.10 g CaCN2)*(3 mol H2O/1 mol CaCN2)*(18g H2O/1 mol H2O) 50.56 g H2O b) How many grams of NH3 are produced from 5.24 g of CaCN2? 5.24g CaCN2 (1 mol CaCN2/ 80.10 g CaCN2)*(2 mol NH3/1 mol CaCN2)*(17g NH3/ 1mol NH3) 2.22g NH3 c) How many grams of CaCO3 form if 155 g of water reacts? 1.55g H2O (1 mol H2O/18g H2O)*(1 mol CaCO3/3 mol H2O)*(100g CaCO3/1 mol CaCO3) 2.87g CaCO3

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