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In the conversion of A into D in the fowling biochemical pathway E A , E B, and

ID: 78163 • Letter: I

Question

In the conversion of A into D in the fowling biochemical pathway EA, EB, and EC have the following Km values indicated under each enzyme. If all of the substrates and products are present at a concertation of 10-4 M and the enzymes have approximately the same Vmax which step will be the rate limiting step. (Please explain why)

                                                                                                  A------->B--------->C-------->D

                                                                                                       EA           EB                 EC

                                                                                          Km:    10-2M       10-4M       10-4M

A. EA

B. EB

C. EC

D. EA and EB

E. EB and EC

Explanation / Answer

Answer: E. EB and EC (As explained below)

The slowest step in a reaction is always the rate-limiting step. So lets find out the step that has the slowest rate.

Rate of reaction for EA = km x EA = 10-2 x 10-2 = 10-4

Rate of reaction for EB = km x EB = 10-2 x 10-4 = 10-6

Rate of reaction for EC = km x EB = 10-2 x 10-4 = 10-6

So, EB and EC is lowest.