Consider the reaction between sodium metal and chlorine gas to form sodium chlor

Question

Consider the reaction between sodium metal and chlorine gas to form sodium chloride (table salt): 2Na(s) + Cl2(g) ? 2NaCl(s) If 12.5 g of sodium react with sufficient chlorine, how many grams of sodium chloride will be formed? Answer                              A. 4.92 g                 B. 9.84 g                 C. 15.9 g                 D. 63.6 g                 E. 31.8 g Consider the reaction between sodium metal and chlorine gas to form sodium chloride (table salt): 2Na(s) + Cl2(g) ? 2NaCl(s) If 12.5 g of sodium react with sufficient chlorine, how many grams of sodium chloride will be formed? 2Na(s) + Cl2(g) ? 2NaCl(s) If 12.5 g of sodium react with sufficient chlorine, how many grams of sodium chloride will be formed? 4.92 g 9.84 g 15.9 g 63.6 g 31.8 g                 A. 4.92 g                 B. 9.84 g                 C. 15.9 g                 D. 63.6 g                 E. 31.8 g

Explanation / Answer

12.5g Na x (1 mol Na)/(22.99g Na) x (2 mol NaCl)/(2 mol Na) x (58.443g NaCl)/(1 mol NaCl) = 31.8g NaCl. So your answer is E.

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