IF anyone can help me with this involved question it would be greatly appreaciat
ID: 810304 • Letter: I
Question
IF anyone can help me with this involved question it would be greatly appreaciated.
the following data were collected from two separate experiments for the following reaction in aqueous, by measuring the number of moles of Hg2Cl2 that precipated per liter per minute
2HgCl2(aq) + C2O4^2-(aq) ---> 2Cl-(aq) + 2CO2(g) Hg2Cl2 (s)
Experiment 1 Experiment 2
time HgCl2 mol/L excess C2O4^2- C2O4^2- mol/L excess HgCl2
0 0.150 0.300
3.33 0.0843 0.283
5.00 0.0755 0.275
6.67 0.0676 0.268
8.33 0.0606 0.261
10.00 0.0543 0.254
16.67 0.0340 0.229
23.33 ? ?
f.) What is the first half life of both HgCl2 and C2O4^2- from the concentration at t=0 minutes?
Thanks, I know this is a long question.
Explanation / Answer
To calculate half-life, it is necessary to find the rate law and rate constant. The later can be found by,
1. Converting the rate of formation of Hg2Cl2 into concentration by multiplying time.
2. Plotting the conc. of Hg2Cl2 against time and fitting the data points by regression method.
3. Based on the regression equation obtained by fitting the data, linearize the curve by converting the data appropriately.
4. The linear fitting equation now gives the rate law and rate constant.
5. Then calculate time for 50% consumption of HgCl2 and oxalate ions.