Please help, i need assistance in figuring this out Consider 100.0 mL of a 2.0 x
ID: 825932 • Letter: P
Question
Please help, i need assistance in figuring this out
Consider 100.0 mL of a 2.0 x 10^-4 M aques solution of F3CSO3H ; pKa = -14.9 for f3CSO3H.
circle the letter of each correct answer. IN water , F3CSO2H is a
A. strong Acid
B. weak acid
C. Strong Base
D. Weak Base
E. Niether acid or base
The pH of this solution is expected to be
A 4.0
B. 3.7
C. 3.70
D. 3.69
E. 4.70
G. Greater than 7
H. 10.30
A 100. mL saple of a 2.0 x 10-4 aques solution of which of the following solutes would give the same pH as 2.0 x 10-4 M F3CCS03H?
A. HC2H3O2
B. HF
C. HBr
D.H2SO4
E. HCIO3
F.NaOh
G. NH3
H. Na Cl
Explanation / Answer
1) pKa = -14.9 for f3CSO3H.
the lower the pKa value the stonger the acid . the acids with negative pKa values are very strong acids
so the answer is A. strong Acid
2) Given 2.0 x 10^-4 M of acid
pH = -log 2 x 10-4
pH = 3.6989
so the pH is 3.689 = 3.70
so the answer is C. 3.70 or may be D .3.69
3) All monoprotic strong acids give the same pH as 2.0 x 10-4 M F3CCS03H.
H2S04 is a strong acid but is dibasic .
so the answer is
C. HBr
E. HCIO3
HCl03 is sometimes considered as a strong acid . Otherwise the answer should be only
C. HBr