Please help me solve these balanced equations! The determination of ascorbic aci
ID: 849604 • Letter: P
Question
Please help me solve these balanced equations!
The determination of ascorbic acid by redox titration involves three redox reactions. Use chem pad to write the complete balanced equation for each of these reactions occurring in acid solution. (Add water and protons to the equations as appropriate. Do not include symbols for the state of matter in your answers. Write monovalent ions in the form (I1-). Reaction of iodate with iodide to form the triiodide ion: Oxidation of ascorbic acid (C6H806) to dehydroascorbic acid (C6H606) by the triiodide ion: Reduction of the excess triiodide with thiosulfate:Explanation / Answer
16. Ans :- Option (B) "NH4OH is not a strong electrolyte " is the correct answer.
Explanation :-
Strong electrolytes:- The substance which are completely dissociated into ions in aqueous solution are known as strong electrolytes . for e.g :- strong acids , strong bases and salts ( i.e chlorides , sulphides , carbonates , sulphates etc.) of alkali, alkaline earth metals and ammonium ions are strong electrolytes .
Weak electrolytes:- The substance which are partially dissociated into ions in aqueous solution are known as weak electrolytes . for e.g :- weak acids , weak bases and salts of Ag and Al are weak electrolytes .
NH4OH is a weak base therefore it is a weak electrolyte while Na2CO3 , Li2SO4 and CaS are strong electrolytes.
CH3 CH2 CH3 i.e Propane is non-electrolyte because it is not dissociated into ions in aqueous solution .