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Problem 13.15 The equilibrium constant K p for the reaction C( s )+H2O( g )???CO

ID: 852102 • Letter: P

Question

Problem 13.15

The equilibrium constant Kp for the reaction C(s)+H2O(g)???CO(g)+H2(g)
is 2.44 at 1000 K. The initial partial pressures are PH2O = 1.27atm , PCO = 1.03atm , and PH2 = 1.39atm .

Part A

What is the equilibrium partial pressure of H2O?

Express your answer with the appropriate units.

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Part B

What is the equilibrium partial pressure of CO?

Express your answer with the appropriate units.

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Part C

What is the equilibrium partial pressure of H2?

Express your answer with the appropriate units.

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Problem 13.15

The equilibrium constant Kp for the reaction C(s)+H2O(g)???CO(g)+H2(g)
is 2.44 at 1000 K. The initial partial pressures are PH2O = 1.27atm , PCO = 1.03atm , and PH2 = 1.39atm .

Part A

What is the equilibrium partial pressure of H2O?

Express your answer with the appropriate units.

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Part B

What is the equilibrium partial pressure of CO?

Express your answer with the appropriate units.

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Part C

What is the equilibrium partial pressure of H2?

Express your answer with the appropriate units.

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Explanation / Answer

Kp= 2.44
C(s)+H2O(g)???CO(g)+H2(g)

Q= p(CO)*p(H2)/p(H2O) = (1.03)*(1.39)/1.27 = 1.127 < Kp
Hence the reaction will proceed forward towards equilibrium

C(s)+H2O(g)???CO(g) + H2(g)
    1.27-x    1.03+x 1.39+x

Kp=(1.03+x)*(1.39+x)/(1.27-x)
x= 0.32

p[H2O]= 1.27 - 0.32 = 0.95 atm
p[CO]= 1.03 + 0.32 = 1.35 atm
p[H2]= 1.39 + 0.32 = 1.71 atm