Mercury(I) ions (Hg 2 2 +) can be removed from solution by precipitation with Cl
ID: 852145 • Letter: M
Question
Mercury(I) ions (Hg22+) can be removed from solution by precipitation with Cl- . Suppose a solution contains aqueous Hg2(NO3)2.
1. Write complete ionic equation to show the reaction of aqueous Hg2(NO3)2 with aqueous sodium chloride to form solid Hg2Cl2 and aqueous sodium nitrate.
please show me.. clear...
Mercury(I) ions (Hg2^2+) can be removed from solution by precipitation with Cl- . Suppose a solution contains aqueous Hg2(NO3)2. 1. Write complete ionic equation to show the reaction of aqueous Hg2(NO3)2 with aqueous sodium chloride to form solid Hg2Cl2 and aqueous sodium nitrate. 2. Write net ionic equation to show the reaction of aqueous {rm Hg_2 (NO_3)_2} with aqueous sodium chloride to form solid {rm Hg_2 Cl_2} and aqueous sodium nitrate. please show me.. clear...Explanation / Answer
Molecular equation:
Hg2(NO3)2(aq) + 2NaCl(aq) = Hg2Cl2(s) + 2NaNO3(aq)
1)
Complete ionic equation:
Hg2^2+(aq) + 2NO3^-(aq) + 2Na^+(aq) + 2Cl^-(aq) = Hg2Cl2(s) + 2Na^+(aq) + 2NO3^-(aq)
spectator ions cancel (those found on both sides of the equation) leaving you with the net ionic equation below.
2)
Net ionic equation:
Hg2^2+(aq) + 2Cl^-(aq) = Hg2Cl2(s)