Describe how we would make the following solutions: (a) 500.0 mL of a 5.32% w/w

Question

Describe how we would make the following solutions: (a) 500.0 mL of a 5.32% w/w H 2 S solution in water (b) 342.0 mL of a 0.443% w/w benzene solution in toluene (c) 12.5 mL of a 34.2% w/w dimethyl sulfoxide solu-tion in acetone Describe how we would make the following solutions: (a) 500.0 mL of a 5.32% w/w H 2 S solution in water (b) 342.0 mL of a 0.443% w/w benzene solution in toluene (c) 12.5 mL of a 34.2% w/w dimethyl sulfoxide solu-tion in acetone Describe how we would make the following solutions: (a) 500.0 mL of a 5.32% w/w H 2 S solution in water (b) 342.0 mL of a 0.443% w/w benzene solution in toluene (c) 12.5 mL of a 34.2% w/w dimethyl sulfoxide solu-tion in acetone

Explanation / Answer

a)

%w/w = [(mass of solute) / (Mass of solute + mass of solvent) ] x 100

Let mass of H2S be x. mass of water = 500 g - x.

So, plugging in the values,

5.32 = [(x) / (x + 500g - x)] x 100

5.32 x 10^-2 = x / 500

x = 26.6 g of H2S

So, 26.6 g of H2S is taken and dissolved in some quantity of water and shaken until H2S dissolves. Then the water is added until the solution is 500g .

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