Hexene is burned with air at an equivilence ratio of 0.84. The heat release rate

Question

Hexene is burned with air at an equivilence ratio of 0.84. The heat release rate is 750 kW, hexene's enthalpy of formation is -43,200 kj/kmol and its lower heating value is 44000 kj/kg. The density of hexene (stored in liquid form) is 673 kg/m^3.

Hexene (C6H12) is burned with air at an equivalence ratio of 0.84. The heat release rate is 750 kW, hexene's enthalpy of formation is -43,200 kJ/kmol. and its lower heating value is 44,400 kJ/kg. The density of hexene (stored in liquid form) is 673 kg/m3. Determine: The mass flow rate of hexene, in kg/s. The volume of fuel consumed n 8 hours of operation, in m3. The mass flow rate of air, in kg/s. The mole fraction of O2 in the products. The mass fraction of CO2 in the products. The adiabatic flame temperature, using 1640 and 2450 K as your guesses.

Explanation / Answer

Heat release rate = 750 kW = 750 kJ/sec

Now, heat released by burning per kg of hexene = 44400 kJ

Thus, mass flow rate of hexene = 750/44400 = 0.0169 kg/sec.........(A)

Now, 8 hrs = 8*3600 = 28800 sec

Now, Total hexene consumed in 8 hrs. (i.e 28800 sec) = mass flow rate of hexene*time = 0.0169*28800 = 486.486 kg

Density of hexene = 673 kg/m3

Thus, volume of hexene consumed in 8 hrs. = mass of hexene consumed/density of hexene = 486.486/673 = 0.723 m3..............(B)

C6H12 + 9O2 -----------> 6CO2 + 6H2O

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