Please answer part 2b and 2c 2. In a population of haploid, asexual yeast living
ID: 89119 • Letter: P
Question
Please answer part 2b and 2c
2. In a population of haploid, asexual yeast living in your left ear, a beneficial mutation (W) arises that allows mutant individuals to consume your ear wax a higher rate that those lacking the mutation. Because these yeasts are asexual and haploid, we can assume that the two alleles, W and w, represent the genotypes of the population. If the mutant genotype (W) is able to reproduce asexually at twice the rate of the non-mutant genotype (w), what is the selection coefficient of each genotype? (W = 4 and w =
2a) If the population at time t=0 is composed of 98 w individuals and 2 W individuals, calculate the following for the population at time t=1: change in genotype numbers, change in genotype frequencies and q (recall: q always represents the inferior genotype).
2b) Using of the entire population as a measure of the population's fitness, carry out the calculations you performed above for a total of 10 generations (t=10). How has changed between t=1 and t=10? What does this mean for the population in regards to their environment?
2c) Ignoring the number of yeast cells that have died, what is the estimated size of the yeast population in your ear at time t=10?
Explanation / Answer
Beneficial mutant W is having a advantageous trait that has brought it with a distinction function. Now here we need to have the population of them to calculate the other measures. Two alleles, W and w, represent the genotype of the population. This means the population has increased a lot.