Part A What is the bond order of I2? Express your answer numerically as an integ

Question

Part A
What is the bond order of I2?
Express your answer numerically as an integer.

Part B
What is the bond order of SO?
Express your answer numerically as an integer.

Part C
What is the bond order of CO?
Express the answer numerically as an integer.

Part D
Rank the following molecules or ions in order of decreasing bond energy:
iodine: I2, sulfur monoxide: SO, carbon monoxide: CO
Rank from highest to lowest bond energy.

Part E
Rank the following molecules or ions in order of decreasing bond length:
iodine: I2, sulfur monoxide: SO, carbon monoxide: CO

Rank from longest to shortest bond.

Explanation / Answer

a) Iodine belongs to the group of flourine and hence possess ns2 np5 configuration, it just requires one electron to share with the other iodine atom in order to complete its ocetet

Hence the bond order of I2 will be equal to 1

I---I

b) Sulphur belongs to the group of oxygen and hence possess ns2 np4 configuration, it just requires two electron to share with the other same group (oxygen) atom in order to complete its ocetet

Hence the bond order of SO will be equal to 2

S=O

c) The carbon required 4 bons in order to complete its octet whereas oxygen requires two bonds, there exists a coordinate bond between the carbon and oxygen in which oxygen donates its share pair of electron to fullfill the ocete of carbom

Bond order of CO = 3

d) Bond energy is proportional to bond order

Hence CO > SO > I2

e) Bond length is inversely proportional to bond order

Hence I2> SO > CO

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