Complete the following table with correct significant figures and units. Please
ID: 910479 • Letter: C
Question
Complete the following table with correct significant figures and units. Please show calculations.
Solution B
The number of moles of NaCl
The number of moles of all solutes (including cations and anions)
Mass of solvent (assume that the density of water is 1.000g/mL
The molality of all solutes
Solution C
The number of moles of NaCl
The number of moles of all solutes (including cations and anions)
Mass of solvent (assume that the density of water is 1.000g/mL
The molality of all solutes
Solution D
The number of moles of NaCl
The number of moles of all solutes (including cations and anions)
Mass of solvent (assume that the density of water is 1.000g/mL
The molality of all solutes
Solution B Solution C Solution D Mass of NaCl 11.69g 5.85g 2.92g Volume of Water 100mL 100mL 100mLExplanation / Answer
Solution B
The number of moles of NaCl: 11.69 g/ (58.44 g/mol) = 0.20 moles
The number of moles of all solutes (including cations and anions): 2*0.2 = 0.40 moles
Mass of solvent (assume that the density of water is 1.000 g/mL): 100 g
The molality of all solutes: 1000*(0.4 /100) = 4 m
Solution C
The number of moles of NaCl: 5.85 g / (58.44 g/mol) = 0.10 moles
The number of moles of all solutes (including cations and anions): 2*0.1 = 0.20 moles
Mass of solvent (assume that the density of water is 1.000 g/mL): 100 g
The molality of all solutes: 1000*(0.2/100) = 2 m
Solution D
The number of moles of NaCl: 2.92 / (58.44 g/mol) = 0.05 moles
The number of moles of all solutes (including cations and anions): 2*0.05 = 0.10 moles
Mass of solvent (assume that the density of water is 1.000 g/mL): 100 g
The molality of all solutes: 1000 * (0.1/100) = 1 m