Consider the following reaction at equilibrium. What effect will reducing the vo
ID: 950947 • Letter: C
Question
Consider the following reaction at equilibrium. What effect will reducing the volume have on the system.
If you could please be distinct in how you figured this problem out it would be really helpful thank you.
Part A Consider the following reaction at equilibrium. What effect will reducing the volume have on the system? CaH8(g) + 5 O2(g)3 CO2(g) + 4 H20(1) H=-2220 kJ The equlibrium constant will decrease. O The equilibrium constant will increase O The equilibrium constant will decrease No effect will be observed O No effect will be observed. O The reaction will shift to the left in the direction of reactants. O The reaction will shift to the right in the direction of products. Submit My Answers Give UpExplanation / Answer
Answer is
The reaction will shift to the right in the direction of products.
If all other factors remain constant, changing the volume occupied by a gas will change its concentration, and therefore, change the rate at which it reacts with other substances.
In general, decreased volume and increased concentration will lead to an increase in both the forward and reverse rates, but it will cause a greater increase in the rate (forward or reverse) whose “reactants” have more moles of gas.
Thus decreased volume for a gas-phase reaction will shift the system toward the side of the reaction with the fewest moles of gas.