The Chemical Reaction of Fe(s) and Cu^2+ (aq) When iron filings are placed in a
ID: 960525 • Letter: T
Question
The Chemical Reaction of Fe(s) and Cu^2+ (aq) When iron filings are placed in a 1.0 M copper (II) sulfate solution and left to stand for a while, copper is removed from solution and deposits on the bottom of the beaker as a red solid, and some Fe^2+ ions are found in solution. Assuming iron is the excess reactant, eventually all of the copper ions will settle out as solid copper. This type of reaction, which involves a transfer of electrons is called an oxidation-reduction, or redox, reaction. Equation 1: Fe(s) + Cu^2+(aq) rightarrow Fe^2+ (aq) + Cu(s) Which reactant in Equation (circle one) Gains electrons? Fe(s) orCu^2+(aq) Loses electrons? Fe(s) or Cu^2+ (aq) a) What is the charge on the solid iron atoms on the left side of the equation? b) What is the charge on the iron ions on the right side of the equation? a) What is the charge on the aqueous copper ions on the left side of the equation? b) What is the charge on the solid copper atoms on the right side of the equation? How many electrons are transferred when ... One iron atom reacts with one Cu^2+ ion? One mole of iron reacts with one mole of Cu^2+? If the solution started as copper (II) sulfate, why aren't the sulfate ions in the above equation?Explanation / Answer
1.Fe -2e- -------> Fe+2 oxidation lose of electrons
Cu+2 + 2e- --------> Cu reduction gain of elctrons
Fe(s) + Cu+2 (aq) --------> Fe+2 (aq) + Cu
2.a.Free state solif iron xidation state is Zero
b.left side iron ion charge is +2 in Fe+2
3. a. Aqueous copper chare is +2 in Cu+2 (aq)
b Left side copper charge is zero ( free state copper)
4. Fe -2e- -------> Fe+2 oxidation lose of electrons
Cu+2 + 2e- --------> Cu reduction gain of elctrons
Fe(s) + Cu+2 (aq) --------> Fe+2 (aq) + Cu over all reaction . In this reaction involve two electrons.
b. Fe -2e- -------> Fe+2 oxidation lose of electrons
Cu+2 + 2e- --------> Cu reduction gain of elctrons
Fe(s) + Cu+2 (aq) --------> Fe+2 (aq) + Cu two moles of electrons are involve in this reaction
5. Fe(s) + CuSO4(aq) --------> FeSO4 (aq) + Cu
SO42- ions are spectator ions . The ions are appearence on the both sides of equation is called spectator ions. So they are remove to get net ionic equation