Please Help! ( A 9.03 mL of chlorobenzene, 6.27 mL of carbon tetrachloride and 1
ID: 1023485 • Letter: P
Question
Please Help! (
A 9.03 mL of chlorobenzene, 6.27 mL of carbon tetrachloride and 11.38 mL of benzene are all mixed in a 50 mL beaker. Please complete all parts, if possible and show work:
a) Calculate the volumetric fraction of each component in the mixture (assuming all volumes are additive)
b) Calculate the mass fraction of each component
c) Calculate the mole fraction of each component
d) Calculate the specific gravity of mixture relative to H2O at 4 degree Celcius
e) Calculate the average molecular weight of the mixture.
Thank you !
Explanation / Answer
a) 9.03 mL of chlorobenzene, 6.27 mL of carbon tetrachloride and 11.38 mL of benzene gives total volume = (9.03 + 6.27 + 11.38) mL = 26.68 mL
Volumetric fraction of chlorobenzene = 9.03 mL/26.68 mL = 0.338
Volumetric fraction of carbon tetrachloride = 6.27 mL/26.68 mL = 0.235
Volumetric fraction of benzene = 11.38 mL/26.68 mL = 0.427
b) density of chlorobenzene = 1.11 g/mL so, mass of chlorobenzene = 9.03 mL * 1.11 g/mL = 10.02 g
density of carbon tetrachloride = 1.59 g/mL so, mass of carbon tetrachloride= 6.27 mL * 1.59 g/mL = 9.97 g
density of benzene = 0.876 g/mL so, mass of benzene = 11.38 mL * 0.876 g/mL = 9.97 g
Hence, total mass = (10.02 + 9.97 + 9.97) g = 29.96 g
Mass fraction of chlorobenzene = 10.02g/29.96 g = 0.334
Mass fraction of carbon tetrachloride = 9.97g/29.96 g = 0.333
Mass fraction of benzene = 9.97g/29.96 g = 0.333
c) Molar mass of chlorobenzene = 112.56 g/mol, hence mole number = 10.02/112.56 = 0.089 mol
Molar mass of carbon tetrachloride = 153.82 g/mol, hence mole number = 9.97/153.82 = 0.065 mol
Molar mass of benzene = 78 g/mol, hence mole number = 9.97/78 = 0.128 mol
So, total mole number = (0.089+0.065+0.128) mol = 0.282 mol
Hence, mole fraction of chlorobenzene = 0.089 mol/0.282 mol = 0.316
mole fraction of carbon tetrachloride = 0.065 mol/0.282 mol = 0.230
mole fraction of benzene = 0.128 mol/0.282 mol = 0.454
d)
Specific gravity of mixture = 1/ [0.334 * 1.11 + 0.333 * 1.59 + 0.333 * 0.876] = 0.839
First 4 sections are answered according to regulations of Chegg. Please post rest of the questions separately.