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Consider the following titration for the next 5 questions (11-15), M HCIOs (in t

ID: 1037887 • Letter: C

Question

Consider the following titration for the next 5 questions (11-15), M HCIOs (in the flask) is titrated with 0.040 M NaOH (in buret) 11. What is the overall reaction occurring in the titration? (a) HCIOdaq) + H2O ? Hyoraq) + C104, (aq) b) HClo (aq)+NaOH(a) HO NaCa)+2 0:(8) (c) HCIo (ag)+NaOH(aq)NaCl0(a)+H2O (d) NaOHaq)+HO HO+O(a) Na(aq) 12. How many ml of the NaOH solution need to be added to reach the equivalence point of (a) 10.0 mL (b) 20.0 mL (c) 30.0 mL (d) 40.0 mL (e) 50.0 mL 13. Which of the following is present in the flask after some NaOH has been added, but (a) HCIO4(aq) 14. Which of the following is present in the flask at the equivalence point of the titration? (a) HCIO4(aq) 15. What is the pH of the solution in the flask at the equivalence point of the titration? the titration? before the equivalence point has been reached? Mark all correct answers. (b) NaOH(ag) (c) NaCIO4(aq) (d) NaCIO (ao) Mark all correct answers. (b) NaOH(aq (c) NaCIO4(aq) (d) NaCIOs(aq) (a) 10.84 (b)5.86 () 8.22 ()7.00 (e) 5.43

Explanation / Answer

11. c. HClO4(aq) + NaOH(aq) -----------------> NaClO4(aq) + H2O(l)

12.    HClO4(aq) + NaOH(aq) -----------------> NaClO4(aq) + H2O(l)

       1 mole          1 mole

HClO4                                                       NaOH

M1   = 0.06M                                              M2 = 0.04M

V1   = 20ml                                                V2 =

n1 =1                                                         n2 =1

                 M1V1/n1   =   M2V2/n2

                      V2       = M1V1n2/M2n1

                                  = 0.06*20*1/0.04*1    =30ml

c. 30.0ml

13. a. HClO4

14.NaClO4

15. at equalent point no of moles of HClO4 = no of moles of NaOH

PH = 7

d.7