Consider the following titration for the next 5 questions (11-15), M HCIOs (in t
ID: 1037887 • Letter: C
Question
Consider the following titration for the next 5 questions (11-15), M HCIOs (in the flask) is titrated with 0.040 M NaOH (in buret) 11. What is the overall reaction occurring in the titration? (a) HCIOdaq) + H2O ? Hyoraq) + C104, (aq) b) HClo (aq)+NaOH(a) HO NaCa)+2 0:(8) (c) HCIo (ag)+NaOH(aq)NaCl0(a)+H2O (d) NaOHaq)+HO HO+O(a) Na(aq) 12. How many ml of the NaOH solution need to be added to reach the equivalence point of (a) 10.0 mL (b) 20.0 mL (c) 30.0 mL (d) 40.0 mL (e) 50.0 mL 13. Which of the following is present in the flask after some NaOH has been added, but (a) HCIO4(aq) 14. Which of the following is present in the flask at the equivalence point of the titration? (a) HCIO4(aq) 15. What is the pH of the solution in the flask at the equivalence point of the titration? the titration? before the equivalence point has been reached? Mark all correct answers. (b) NaOH(ag) (c) NaCIO4(aq) (d) NaCIO (ao) Mark all correct answers. (b) NaOH(aq (c) NaCIO4(aq) (d) NaCIOs(aq) (a) 10.84 (b)5.86 () 8.22 ()7.00 (e) 5.43Explanation / Answer
11. c. HClO4(aq) + NaOH(aq) -----------------> NaClO4(aq) + H2O(l)
12. HClO4(aq) + NaOH(aq) -----------------> NaClO4(aq) + H2O(l)
1 mole 1 mole
HClO4 NaOH
M1 = 0.06M M2 = 0.04M
V1 = 20ml V2 =
n1 =1 n2 =1
M1V1/n1 = M2V2/n2
V2 = M1V1n2/M2n1
= 0.06*20*1/0.04*1 =30ml
c. 30.0ml
13. a. HClO4
14.NaClO4
15. at equalent point no of moles of HClO4 = no of moles of NaOH
PH = 7
d.7