Blocks of mass 15, 30, and 90 kg are lined up from left to right in that order o

Question

Blocks of mass 15, 30, and 90 kg are lined up from left to right in that order on a frictionless surface so each block is touching the next one. A rightnard-pointing force of magnitude 24 N is applied to the left-most block. 13) What is the magnitude of the force that the left block exert on the middle one? N 14) What is the magnitude of the force that the middle block exert on the left one? N 15) What is the magnitude of the force that the middle block exerts on the rightmost one? N 16) Now the position of the right two masses are flipped. What is the magnitude of the force that the middle block exerts on the right block? N

Explanation / Answer

net acceleration of all three block=a=F/(M1+M2+M3)

=.18 m/s^2

a) force exerted by left one on middle =a*(M2+M3)=.18*(30+90)=21.6N

b)force on left one by middle=F-aM1=24-2.7=21.6 N

c)force by middle on right =a*M3=16.2 N

Related Questions

Navigate

• Browse (All)
• Browse B
• Subjects

---