An object with mass 60 kg moved in outer space. When it was at location < 10, -2
ID: 1282449 • Letter: A
Question
An object with mass 60 kg moved in outer space. When it was at location < 10, -23, -5 > its speed was 5 m/s. A single constant force < 250, 450, -170 > N acted on the object while the object moved from location < 10, -23, -5 > m to location < 15, -17, -8 > m. Then a different single constant force < 150, 240, 160 > N acted on the object while the object moved from location < 15, -17, -8 > m to location < 19, -22, -2 > m. What is the speed of the object at this final location?
Explanation / Answer
force=F=ma=mv/t=mv/(d/v)=mv2/d
in the second case we are given F,m and d, we can find the velocity v