An object with mass 60 kg moved in outer space. When it was at location < 13, -1

Question

An object with mass 60 kg moved in outer space. When it was at location < 13, -19, -3 > its speed was 3.5 m/s. A single constant force < 220, 320, -120 > N acted on the object while the object moved from location < 13, -19, -3 > m to location < 18, -11, -8 > m. Then a different single constant force < 150, 230, 220 > N acted on the object while the object moved from location < 18, -11, -8 > m to location < 22, -17, -3 > m. What is the speed of the object at this final location?
final speed = m/s

Explanation / Answer

r01 = (18-13)i + (-11- (-19))j + (-8 - (-3))k = 5i + 8j - 5k

|r01| = 5^2 + 8^2 +5^2 = 10.68 m

|F1| = 220^2 + 320^2 + 120^2 = 406.45 N

a =F1/m = 406.45/60 = 6.77 m/s2

v2 - u^2 = 2as

v^2 - 3.5^2 = 2 x 10.68 x 6.77

v = 12.52 m/s

again similarly,

R02 =42 + 62 + 52 = 8.77 m

a = 1502 + 2302 + 2202 / 60 = 5.86 m/s2

v2 - u^2 = 2as

v^2 - 12.52^2 = 2 x 8.77 x 5.86

v = 16.22 m/s

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