A small 8.30-kg rocket burns fuel that exerts a time-varying upward force on the

Question

A small 8.30-kg rocket burns fuel that exerts a time-varying upward force on the rocket. This force obeys the equation F=A+Bt2. Measurements show that at t=0, the force is 130.0 N , and at the end of the first 1.60 s , it is 155.0 N .

Part A

Find the constant A.

A=130 N

Part B

Find the constants B.

B=9.77 N/s2

Part C

Find the net force on this rocket the instant after the fuel ignites.

(130 N is not the answer i dont know why)

Part D

Find the acceleration of this rocket the instant after the fuel ignites.

Part E

Find the net force on this rocket 4.80 s after fuel ignition.

Part F

Find the acceleration of this rocket 4.80 s after fuel ignition.

Part G

Suppose you were using this rocket in outer space, far from all gravity. What would its acceleration be 4.80 s after fuel ignition?

Explanation / Answer

a)

given force equation

F=A+Bt^2

substitue t=0 in force equation.

130N=A

b)Putting t=2.2 in equation,

155=130+B*1.6^2

B=9.77N/s^2

c)

Net force

F ( net) = A- mg

130-mg=130-8.3*9.8=48.66N

d)

a=Net force/m= 48.66 N/8.3

=5.86m/s^2

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