Mastering Physics: Chap 28 (deadliine: 10:00 pm, Saturday, 10/17/15) Google Chro

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Mastering Physics: Chap 28 (deadliine: 10:00 pm, Saturday, 10/17/15) Google Chrome https://session.masteringphysics.com/myct/itemView?offset next&assignmentProblemlD; 51391697 PHY 132 Classical Physics ll Fall 2015 Signed in as Hy Bin Kim l Help l Close Resources Chap 28 deadline 10.00 pm Saturda Problem 28.52 previous l 15 of 17 I next Problem 28.52 Part A Three long parallel wires are 3.5 cm from one another. (Looking along them, they are at three corners of an equilateral triangle.) The current in each wire is 8.00 A, but its direction in wire M is e(Eigure 1) ine the magnitude of t agnetic field midway between points M and N. d P (S Express your answer using two significant figures. B 0.0117 Submit My Answers Give Up Incorrect, Try Again, 5 attempts remaining Part B Determine the direction of the magnetic field. Express your answer using two significant figures. a 300 o below the horisontal direction Submit My Answers Give Up Figure 1 of 1 Incorrect, Try Again; 5 attempts remaining Provide Feedback Continue NH- 3.5 cm HP 9.34 2015-10-17

Explanation / Answer

at the midpoint between M and N,the magnetic filed due to the currents at M and N are in the
same direction

BM+BN = 2*mu_0*i*/(2*pi*r) = 2*4*3.142*10^-7*8/(2*3.142*(0.035/2)) = 1828.57*10^-7 T

te magnetic field due to current at p is BP = mu_o*i/(2*pi*r)

r is the distance from P to the midpoint between M and N

r^2 = 0.035^2- (0.035/2)^2

r = 0.0303 m

then BP = (4*3.142*10^-7*8)/(2*3.142*0.0303) = 527.86 *10^-7 T

then required magnetic field is B = sqrt(527.86^2 + 1828.57^2)*10^-7 = 1903.23 *10^-7 T

theta = atan(527.86/1828.57) = 16.1 degrees

and required angle is 180-16.1 = 163.9 degrees above the horizontal axis

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