Consider the circuit shown in the diagram below. The battery has a voltage V = 1

Question

Consider the circuit shown in the diagram below. The battery has a voltage V = 12.0 V and the resistors have the following values.

R1 = 1.61 ?; R2 = 3.22 ?; R3 = 8.05 ?; R4 = 4.83 ?

How much current flows through each of the four resistors?

I1 = A I2 = A I3 = A I4 = A Consider the circuit shown in the diagram below. The battery has a voltage V = 12.0 V and the resistors have the following values. R1 = 1.61 ?; R2 = 3.22 ?; R3 = 8.05 ?; R4 = 4.83 ? How much current flows through each of the four resistors?

Explanation / Answer

R2 , R3 AND R4 ARE IN PARALLEL SO EQUIVALENT RESISTANCE.....

REQ = 1.558 OHMS

AND REQ AND R1 ARE IN SERIES

REQ ( FINAL ) = 1.61 + 1.558

= 3.168 OHMS

TOTAL CURRENT = I = V/R

= 12 / 3.168

=3.7878 OHMS

CURRENT IN R1 --------------->>> R1 IS IN SERIES SO CURRENT = TOTAL CURRENT =3.7878 A

CURRENT IN R2 , R3 , R4 -------->>>> R2,R3,R4 ARE IN PARALLEL = 3.7878/3= 1.26 A

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