A rectangular coil 0.10 m by 0.20 m is located in uniform magnetic field of B=0.

Question

A rectangular coil 0.10 m by 0.20 m is located in uniform magnetic field of B=0.250 T. Find the magnetic flux through the coil when the plane of the coil is (a) perpendicular to the magnetic field B, (b) parallel to the magnetic field B, (c) makes an angle of 60.0 degree wilh the magnetic field B. Determine the change in magnetic flux for all three situations if this magnetic field was (1) increased in two times and (2) decreased in two times (Notice: the change in a magnetic field is Delta B = B final - B initial)

Explanation / Answer

Here ,

Area , A = 0.10 * 0.20 = 0.02 m^2

B = 0.25 T

a) perpendicular to the magnetic field ,

Flux = B*A* cos(0)

FLux = 0.25 * 0.02

Flux = 5 *10^-3 T.m^2

b)
for loop parallel to field

FLux = B*A* cos(90)

Flux = 0 T.m^2

c)

for angle 60 degree

FLux = B*A*cos(90 - 60)

FLux = 0.25 * 0.10 * cos(30)

Flux = 4.33 *10^-3 T.m^2

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