A current of I amperes runs The direction of the current is i A to the far left.
ID: 1399646 • Letter: A
Question
A current of I amperes runs The direction of the current is i A to the far left. CD is also straight and continues far beyond D ion. C, ACP is a straight line. amperes runs through a very, very, long wire of which a portion (ACD) is shown below ndicated. That angle at C is 90°. CA is straight and continues beyond . The point P is a distance d meters C d P (a) [25 points) Calculate the magnetic field at point P that is due to the top wire. Use the Biot-Savart law to do so. (b) [25 points] Now calculate the magnetic field at P that is contributed by the rightmost wire. (Hint: this problem can be done quickly without very complicated math; but you do need to explain your thinking! ) Question 5 continues...Explanation / Answer
a)
As the point P is in the line of flow of current, so while integrating using the Biot Savart Law, the vector integral comes out to be 0 as the angle subtended at the point P is 0 <--------answer
b)
Now, imagining the section CD as half the section of an infinite wire running , we can calculate that the magnetic field due this half infinite section would be half that of the infinite wire
Magnetic field due to infinite wire, B = u*I/(2*pi*r)
where u = permeability = 1.26*10^-6
I = current
r = d
So, the required magnetic field, Breq = u*I/(4*pi*d) <-------answer