Part A) What must the emf in the figure be in order for the current through 7.00

Question

Part A) What must the emf in the figure be in order for the current through 7.00-OHM resistor to be 1.76 A? Each emf source has negligible internal resistance.
Part B) What is the amount of current through the 24.0-V battery?
Part C) What is the amount of current through the 2.0-OHM resistor?
For part A, The answer is 8.05V. I know what the set up looks like, The set up looks like 0 = 24V-((1.76A*7OHM)) - I(3OHM).. but can you please show how to set that up?
I also would like step-by-step instructions on how to set up and solve B and C.

Explanation / Answer

here,

let the current in the 24 V battery be i1

let the current in 2 ohm resistance be i2

curent in 7 ohm resistance is 1.76 A

using KCL in the left smaller loop

E - 2 * i2 + 3 * i1 - 24 = 0 ....(1)

using KCL in the bigger loop

7 * 1.76 + 3 * i1 = 24

i1 = 3.89 A

using KVL

1.76 - i1 - i2 = 0

1.76 - 3.89 - i2 = 0

i2 = 2.13 A

as there is same potential in the parallel

E = 7 * 1.76 - 2 * 2.13

E = 8.05 V

(b)

the amount of current through 24 V battery is 3.89 A

(c)

the amount of current through 2 ohm resistor is 2.13 A

Related Questions

Navigate

• Browse (All)
• Browse P
• Subjects

---