Mastering Physics: Homework #05 (phy 111) Google Chrome https:// mastering physi

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Mastering Physics: Homework #05 (phy 111) Google Chrome https:// mastering physics.com /myct/itemView? assignment ProblemID 517483718 offset 3next Session PHY 1 Fall 2015 Homework #05 (phy 111 Problem 2.53 That's a lot of hot a Part E Problem 2.53 That's a lot of hot air! How many seconds after its release will the bag strike the ground? A hotair balloonist, rising vertically with a constant speed of 5.00 m/s, releases a sandbag at the instant the balloon is 40.0 m above the ground. (See the figure (Figure 1)) After it is released, the sandbag encounters no appreciable air drag. Submit My Answers Give Up Part F How fast is it moving as it strikes the ground? Figure 1 of 1 00 mm/S Submit My Answers Give U Part G What is the greatest height above the ground that the sandbag reaches? 40.0 m to ground hnamax 3 Signed Help Close Resources previous l 8 of 9 l next

Explanation / Answer

this is in continuation of prev question of time 0.255 sec later problem :

part E .

u=-5, h=40, g=9.81, t=?

h= ut + .5 gt^2

40= -5t + .5*9.81 t^2

4.905t^2-5t-40=0

solving this as ax^2 + bx + c = 0

we get two solutions t=3.41 and -2.39

accepting only positive value, t=3.41 s

part F :

again u=-5, t=3.41s, g=9.81, v=?

v=u+gt

=-5 + 9.81*3.41

=28.4521

at the moment it strikes ground, v=28.4521 m/s

6. u=5, v=0, g=-9.81, h=?(in this case upward being positive)

v^2 = u^2 + 2gh

0=5^2 - 2*9.81*h

h=1.274m

greatest height above ground 40+h

H = 41.274m

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