Class Management I Help hapter 7 Begin Date: 6/4/2016 12:00:00 AM Due Date: 6/11

Question

Class Management I Help hapter 7 Begin Date: 6/4/2016 12:00:00 AM Due Date: 6/11/2016 1 00:00 AM End Date: 6/18/2016 12:00:00 AM (8%) Problem l: The pump in a water tower lifts water with a density of pr 1.00kg/lter from a filtered pool at the bottom of the tower up hr 24 m to the top of the tower. The water begins at rest in the pool and comes to rest at the top of the tower. The pump is 100% efficient in lifting the water, and it lifts a volume of 5.6 liters of water up the tower every second. The water tower sits on a hill that is T 15 m above sea level Let gravitational potential energy be zero at ground level P, in Watts, of the pump. lil A 33% Part 0) If the pump runs for 2.8 hours, calculate the increase in the potential energy, AU in J, of the water in the tower A 33% Part (e) The water tower, when full, holds 106 liters of water calculate the gravitational potentialenergy of the water, U full water tower relative to sea level Grade Sua

Explanation / Answer

Part b) Increase in potential energy = mgh

                                                          = (1 * 5.6) * 9.8 * (24 - 15) * 2.8 * 3600

                                                          = 4978713.6 J

Part c)   Gravitational potential energy of water =   (1 * 106) * 9.8 * 19.5

                                                                            = 1.911 * 108 J

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