If you could show all the work for A and B, Thanks You\'re standing on a cliff o

Question

If you could show all the work for A and B, Thanks

You're standing on a cliff overlooking the ocean when you suddenly feel the need to throw a rock over the cliff into the ocean. You calculate the height from your point of view to the water to be H = 225m. You notice that between you and the ocean there is a hump h = 150m in height above the water that you must clear as you throw the rock. If you throw the rock at an angle of theta = 18.5degree below the horizontal, with what initial velocity V_0 must it be thrown in order to overcome/surpass the hump h and reach the ocean? What is the total distance from where you stand on the x-axis to the point the rock enters the water?

Explanation / Answer

a)

vix= vicos(-18.5)

viy=visin(-18.5)

h = H – h = 225 - 150 = 75 m

x= h*tan(18.5)= 75*tan(18.5) = 25.095 m

Along horizontal,

x= vix*t

25.095= vicos(-18.5)*t

t= 25.095/vicos(-18.5) -------------(1)

Along vertical,

h = viy^2 – 1/2gt^2

- 25.095 = [visin(-18.5)]^2 – ½*9.8*[25.095/vicos(-18.5)]^2     => vi= 18.6 m/s

b) H = viy -1/2gt^2

-250 = [17.6sin(-18.5)]^2 – ½*9.8*t^2   => t= 7.6s

d= vix*t = 18.6cos(-18.5)*7.6 = 134.0m

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