If you could show a step by step solution that would be great. 12. -12 points Ka
ID: 1584984 • Letter: I
Question
If you could show a step by step solution that would be great. 12. -12 points KatzPSE1 27 P.059 My Notes Ask Your Teache A parallel-plate capacitor with a gap of 0.210 mm is filled with a dielectric with constant x - 4.10. (a) When the capacitor's potential difference is 59.0 V, what is the energy density? J/m3 (b) Find the average energy density in an AA battery. A typical new alkaline AA battery stores 9.00 × 103 J of electrical energy and has a volume of 8.30 cm3 J/m3 Need Help? Read It Watch ItExplanation / Answer
(A) C = e0 k A / d
Energy stored, U = C V^2 / 2
= e0 k A V^2 / 2 d
Volume = A d
Energy density = e0 k V^2 / 2 d^2
= (8.854 x 10^-12)(4.10)(59^2)/(2 x (0.210 x 10^-3)^2)
= 1.433 J/m^3
(B) Energy density = (9 x 10^3 J ) / (8.30 x 10^-6 m^3)
= 1.08 x 10^9 J/m^3