In the figure below, find the following. (Let e m f1 = 23.0 V, e m f2 = 13.0 V,

Question

In the figure below, find the following. (Let e m f1 = 23.0 V, e m f2 = 13.0 V, and R = 12.0 ?.)

(a) the current in each resistor

(b) the power delivered to each resistor

In the figure below, find the following. (LetEj = 23.0 v, 2 = 13.0 V, and R = 12.0 .) -, + 12.012 (a) the current in each resistor 11 = .485 12-196 13 = .681 Your response differs from the correct answer by more than 10%. Double check your calculations. A Your response differs from the correct answer by more than 10%. Double check your calculations. A (b) the power delivered to each resistor p1 = 6.6 p2 = 4.61 Your response differs from the correct answer by more than 100%. 5.57 Your response differs from the correct answer by more than 10%. Double check your calculations. w

Explanation / Answer

Here,

E1 = 23 V ; E2 = 13 V
R1 = 28 ohm ; R2 = 12 ohm ; R = 12 ohm
Lets operate generators one at a time :
signs are according to the arrows you have shown

a) E1 conducting
Rt1 = R1+R//R2 = 28+12*12/(12+12) = 28+6.0 = 34.0 ohm
I1' = E1/Rt1 = 23/34.0 = 0.6765 A
I2' = -I1'*R/(R+R2) = -0.6765*12/24 = -0.3382 A
I3' = I1'*R2/(R+R2) = 0.6765*12/24 = 0.3382 A

B) E2 conducting
Rt2 = R2+R//R1 = 12+28*12/(28+12) = 12+8.4 = 20.4 ohm
I2" = E2/Rt2 = 13/20.4 = 0.637 A
I1" = -I2"*R/(R+R1) = -0.637*12/40 = -0.1911 A
I3" = I2"*R1/(R+R1) = 0.637*28/40 = 0.4459 A

Currents overlapping :
I1 = I1'+I1" = 0.6765 -0.1911 = 0.4854 A ; P1 = 0.4854^2*28 = 6.60 watt
I2 = I2'+I2" = 0.637-0.3382 = 0.2988 A ; P2 = 0.2988^2*12 = 1.07 watt
I3 = I3'+I3" = 0.3382+0.4459 = 0.7841 A ; P3 = 0.7841^2*12 = 7.38 watt

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