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A current-carrying solenoid is 30 cm long and is wound with 1300 turns of wire.

ID: 1461064 • Letter: A

Question

A current-carrying solenoid is 30 cm long and is wound with 1300 turns of wire. It produces a magnetic field of 4.0×104 T at the solenoid's center.

How long would you make the solenoid in order to produce a field of 6.0×104 T at its center?

Express your answer using two significant figures.

Adjusting only the windings, what number would be needed to produce a field of 8.0×104 T at the center?

Express your answer using two significant figures

What current in the solenoid would be needed to produce a field of 9.0×104 T but in the opposite direction?

Express your answer using two significant figures.

Explanation / Answer

length of the solenoid l=30cm

no of turns N=1300

magnetic field B=4*10^-4 T

let current si i

B=uo*N*i/l

(4*10^-4)=(4pi*10^-7)*(1300)*(i)/(0.3)

====> i=73.46*10^-3 A

current B=73.46 mA

a)

B=uo*N*i/l

(6*10^-4)=(4pi*10^-7)*(1300)*(73.46*10^-3)/(l)

====> l=0.2 m

length l=20 cm


b)

B=uo*N*i/l

(8*10^-4)=(4pi*10^-7)*(N)*(73.46*10^-3)/(0.3)

no of turns N=2599.86

or

N=2600

c)

B=uo*N*i/l

(9*10^-4)=(4pi*10^-7)*(1300)*(i)/(0.3)

====> i=0.165 A

currnet i=0.165 A