A current-carrying solenoid is 10 long and is wound with 1200 turns of wire. It

Question

A current-carrying solenoid is 10 long and is wound with 1200 turns of wire. It produces a magnetic field of 2.0×10-4 at the solenoid's center.


How long would you make the solenoid in order to produce a field of 3.0×10-4 at its center?
Express your answer using two significant figures.
=6.7
Correct


Part B
Adjusting only the windings, what number would be needed to produce a field of 4.0×10-4 at the center?
Express your answer using two significant figures.
=

turns



Part C
What current in the solenoid would be needed to produce a field of 1.1×10-3 but in the opposite direction?
Express your answer using two significant figures.
=7.3×10-2 opposite the original current direction
Correct
****** i NEED HELP WITH PART B

Explanation / Answer

field at centre B=(0NI)/L

field directly proportional to number of truns and current

inversely proposrtional to length

therefore B1/B2 = L2/L1 if N and I is constant.

B1/B2 = N1/N2 if I and L is constant.

B1/B2 = L2/L1

L2 = 10x2/3 = 6.67

B1/B2 = N1/N2

N2 = 4/2 x 1200 = 2400

1.1x10-3 = 4x10-7 x1200 xI /10

I =7.29

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