The diagram below shows a wire loop moving downward through a magnetic Field of

Question

The diagram below shows a wire loop moving downward through a magnetic Field of 2 Tesla with a constant velocity v = 2 m/sec. Gravity is also pulling it in the same direction. The loop has length b =20 cm, width a = 10 cm, and a mass of 20 grams. The resistance of the wire loop is.01 Ohms. The acceleration of gravity is 9.8 m/s. Assume that at time t=0, the loop is just exiting the field, as shown in the diagram. Find the current in the loop, and determine the direction of the current. Sketch a graph of the current as a function of time. In order to keep the loop moving at a constant velocity, an external force is required. (Otherwise gravity would make it accelerate!) Find the magnitude and direction of this external force as the loop is moving through the field.

Explanation / Answer

a)

EMF induced = BVL

current = BvL/R

here L = a

i = 40 A( anti clockwise direction)

b)

since induced EMF is constant

the graph between i and t will be straight line parallel to x axis

c)

Fb + mg + F = 0

Fb = ia b = -8N

mg = 0.196

therefore

F = 7.804N downward

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---