Mastering Physics: Hos: Chapter 4 Dynamics: Newton\'s Laws of Motion Part 2) sec

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Mastering Physics: Hos: Chapter 4 Dynamics: Newton's Laws of Motion Part 2) secure httpsollsession assignment ProblemlD 73212606&offset; next PHY116W2017PEIRIS in Ibrahim Signed in as y Chapter 4 Dynamics Newton previous 8 of 14 l ng Item 8 Part A A car can decelerate at 430 m/s without What would its deceleration be if the road were inclined at 10 uphit? Assume the same statio friction skidding when coming to rest on a level road. coefficient. Express your answer using two significant figures. m/s Submit My Answers give up Continue SO

Explanation / Answer

frictional force is f = mu_s*m*g = m*a

m cancels on both sides

mu_s*g = a

coefficient of static friction is mu_s = a/g

mu_s = 4.3/9.8 = 0.438

on the inclined plane

mu_s*m*g*cos(theta) + m*g*sin(theta) = m*a

m cancels

(0.438*9.8*cos(10)) + (9.81*sin(10)) = a

a = 5.93 m/s^2

for deccelaration a = -5.93 m/s^2

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