Problem 11: Apositive charge of magnitude Qi 65 nC is located at the origin. A n

Question

Problem 11: Apositive charge of magnitude Qi 65 nC is located at the origin. A negative charge Q2 -55 nC is located on the positive x-axis at x 135 cm from the origin. The point Pis located y 145 cm above charge Q2. Ctheexpertta.com Part (a) Calculate the x-component of the electric field at point P due to charge e. Write your answer in units of NIC. Numeric A numeric value is expected and not an expression. Part (b) Calculate the y-component of the electric field at point Pdue to charge Qr. Write your answer in units of NIC. Numeric A numeric value is expected and not an expression, Part (c) Calculate the y component of the electric field at point Pdue to the Charge Q2. Write your answer in units of NIC. Numeric A numeric value is expected and not an expression. Part (d) Calculate the y component of the electric field at point Pdue to both charges. Write your answer in units of NIC. Numeric A numeric value is expected and not an expression.

Explanation / Answer

Here,

Q1 = 6.5 nC

angle of electric field due to Q1 with x axis , theta = arctan(14.5/13.5)

theta = 47 degree

part a)

electric field , E1 = k * q/R^2

E1 = 9*10^9 * 6.5 *10^-9/(0.145^2 + 0.135^2)

E1 = 1490.5 N/C

x component of electric field = E1 * cos(theta)

x component of electric field = 1490.5 * cos(47 degree)

x component of electric field = 1015.7 N/C

part b)

due to y component

y component of electric field = E1 * sin(theta)

y component of electric field = 1490.5 * sin(47 degree)

y component of electric field = 1090.1 N/C

part C)

due to charge Q2

y component of electric field = -k * Q2/y^2

y component of electric field = -9 *10^9 * 5.5 *10^-9/0.145^2

y component of electric field = -2354.3 N/C

part D)

y component of the electric field due to both charges = Ey1 + Ey2

y component of the electric field due to both charges = 1090.1 -2354.3

y component of the electric field due to both charges = -1264 N/C

part e)

net electric field = sqrt(Ex^2 + Ey^2)

net electric field = sqrt(1264^2 + 1090.1^2)

net electric field = 1669.3 N/C

part f)

angle in degree at point P = arctan(-1264/1090.1)

angle in degree at point P = -49.2 degree

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