In the circuit shown in (Figure 1) , E = 66.0 V , R 1 = 4.00 , R 2 = 6.00 and R

Question

In the circuit shown in (Figure 1) , E = 66.0 V ,R1 = 4.00 , R2 = 6.00 and R3 = 3.00 .

What is the potential difference Vab between points a and b when the switch S is open?

Express your answer with the appropriate units.

Part B

What is the potential difference Vab between points a and b when the switch S is closed?

Express your answer with the appropriate units.

Part C

For the 4.00 resistor, calculate the current through the resistor with S open.

Express your answer with the appropriate units.

Part D

For the 4.00 resistor, calculate the current through the resistor with S closed.

Express your answer with the appropriate units.

Part E

For the 6.00 resistor, calculate the current through the resistor with S open.

Express your answer with the appropriate units.

Part F

For the 6.00 resistor, calculate the current through the resistor with S closed.

Express your answer with the appropriate units.

Part G

For the 3.00 resistor, calculate the current through the resistor with S open.

Express your answer with the appropriate units.

Part H

For the 3.00 resistor, calculate the current through the resistor with S closed.

Express your answer with the appropriate units.

Part I

Explanation / Answer

A)When the switch is open, the drop across ab will be that across R2,

Req = 6 + 3 = 9

I = V/R = 66/9 = 7.33

V2 = I2 R2 = 7.33 x 6 = 44 Volts

Hence,Vab = 44

B)When the switch is closed

R12 = 4 x 6/(4 + 6) = 2.4 Ohm

Req = 2.4 + 3 = 5.4 Ohm

I = V/R = 66/5.4 = 12.22 A

drop at R3 = I3 R3 = 12.22 x 3 = 36.67 V

So, Vab = 66 - 36.67 = 29.33 V

Hence, Vab = 29.33 V

C)When the switch is open, the current from R4 is 0

I4 = 0

D)when the switch is closed

Vab = 29.33 V

voltage across the resistors connected in parallel is same

V4 = 29.33 V

I4 = V4/R4 = 29.33/4 = 7.33 A

Hence, I4 = 7.33 A

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