Consider the circuit shown. Find the current through each resistor using the rul

Question

Consider the circuit shown. Find the current through each resistor using the rules for series and parallel resistors. R1=11ohms, R2=6.2ohms,R3=7.5ohms, R4=12ohms. Voltage of battery is 15v. Could you please leave detailed explanation on how to solve this using series and parallel rules. I already solved for the total current running through the battery to be .92 A. However, I am having trouble finding the current running through all the individual resistors. Could you please detail description of how you would solve for current through R3, R4,and R2. Thank you much!

Explanation / Answer

Since the total current running through the battery, I = 0.92 A

Voltage drop across resistance R1, V1 = I*R1 = 0.92*11 = 10.12 V

So, the voltage across A and B, V(A-B) = V(total) - V1 = 15 - 10.12 = 4.88 V

The current flowing through resistance R3,

  I(3) = V(A-B) / R3 = 4.88 / 7.5 = 0.65 A

The current flowing through resistance R2 and R4:

Current flowing through resistance R2 = Current flowing through resistance R4 = V(A-B) / (R2 + R4)

= 4.88 / (6.2 + 12) = 4.88 / 18.2 = 0.268 A

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