Show all work and include equations to find L and C In problem two you will plac

Question

Show all work and include equations to find L and C

In problem two you will place the mathematical datum at the zero point for the meter stick. All moment arms will be measured from there. This will force you to use both the sum of the torques and the sum of the forces because L will have a torque at 30[cm], but L will not be known. You must then find Cat Cm Again, start at the far left and sum the torques and forces as you move to the right. your math for problem two using symbols (a, A, l, L, b, B, c, C) instead of numbers. Solve completely for C, en write down that generalized equation. Finally, evaluate C by using the values for a, A, I, L, b, B, c.

Explanation / Answer

here sum of all torques and sum of all the forces must be zero.

Sum of all forces = A+B+C - L = 0

or A+B+C = L --------- (1)

Sum of all torques = Aa + Bb + Cc - Ll = 0

or Aa + Bb + Cc = Ll ----------- (2)

putting value of L from equation (1) in equation (2) we get

Aa + Bb + Cc = (A+B+C)l

or Cc = (A+B+C)l - Aa - Bb

or C(c-l) = (A+B)l - Aa - Bb = A(l-a) + B(l-b)

or C = [A(l-a) + B(l-b)]/(c-l) ---------- (3)

or C = [550gX9.8m/s2(30cm-10cm) + 160gX9.8m/s2(30cm-54cm)]/(90cm-30cm)

or C = 119.33gX9.8m/s2

putting value of C from equation (3) in equation (1) we get

A+B+[A(l-a) + B(l-b)]/(c-l) = L

or L = A+B+[A(l-a) + B(l-b)]/(c-l) ------------ (4)

or L = A+B+C = [550g+160g+119.33g]X9.8m/s2 = 829.33gX9.8m/s2 (we got the value of C above)

using values of A, a, B, b and l we can easily calculate C and L.

This concludes the answers. If you find anything lacking please let me know.. I will resolve your query without delay....

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