Consider the motion diagram of a point particle shown in the figure below. (a) W
ID: 1654064 • Letter: C
Question
Consider the motion diagram of a point particle shown in the figure below. (a) What is the sign of the position of the particle at all times shown? (circle one) Positive (+) Negative (-) (b) What is the sign of the velocity of the particle at all times shown? (circle one) Positive (+) Negative (-) (c) What is the sign of the acceleration of the particle at all times shown? (circle one) Positive (+) Negative (-) (d) On the motion diagram, draw and label the position vector, velocity vector and acceleration vector of the particle at t = 2s (Chapt 1) Using the conversion factors given on the first page, convert the following quantities to the units indicated (a) Express the length 0.732 m in inches (in). Be sure to truncate your result to the appropriate number of significant figures. (b) Express the speed 66.6 mph (mi/hr) in meters per second (m/s). Be sure to truncate your result to the appropriate number of significant figures. (c) Express the mass density 71.5 kg/m^3 in slugs per cubic foot (slug/ft^3). Be sure to truncate your result to the appropriate number of significant figures.Explanation / Answer
a) At all times shown, the particle is at the negative side of the axis. Answer is negative
b)The particle is moving towards the positve direction. Therefore, the velocity is positive
c)In every time interval, the distance travelled is decreasing .This means the velocity in positive direcxtion is decreasing. Therefore, acceleration is in the negative direction.