Physics 222 Homework 1 (Chapter 12.8,13) Problem 12.32 - Enhanced - with Feedbac

Question

Physics 222 Homework 1 (Chapter 12.8,13) Problem 12.32 - Enhanced - with Feedback A 5.4 kg cat and a 2.3 kg bowl of tuna fish are at opposite ends of the 4.0-m-long seesaw. (Figure 1) PartA How far to the left of the pivot must a 4.0 kg cat stand to keep the seesaw balanced? Express your answer to two significant figures and include the appropriate units. You may want to review (Pages 312-314) Figure 1of1 d1.50 m Submit Previous Answers Request Answer xIncorrect: Try Again; 2 attempts remaining 2.0 m 2.0 m Provide Feedback

Explanation / Answer

Taking moment about the center we have

mcat*g*d = mbowl*g*2 + 4*g*d

5.4*g*2 = 2.3*g*2 + 4*g*d

d = 1.55 m

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