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For the circuit in the figure, what is thecurrent through the 2.0 (omega) resist

ID: 1669156 • Letter: F

Question

For the circuit in the figure, what is thecurrent through the 2.0 (omega) resistor? For the circuit in the figure, what is thepower dissipated by the 20 omega resistor? I know the formula is V=IR for the first onebut the answer I keep coming up with is wrong! Can anyone help me?Im not even sure how to start the second question, For the circuit in the figure, what is thecurrent through the 2.0 (omega) resistor? For the circuit in the figure, what is thepower dissipated by the 20 omega resistor? I know the formula is V=IR for the first onebut the answer I keep coming up with is wrong! Can anyone help me?Im not even sure how to start the second question, For the circuit in the figure, what is thepower dissipated by the 20 omega resistor? I know the formula is V=IR for the first onebut the answer I keep coming up with is wrong! Can anyone help me?Im not even sure how to start the second question,

Explanation / Answer



Left loop: i1 Right loop: i2
Loop i1: 20i1 + 5(i1 - i2) = 0       25i1 - 5i2 = 0          (1)
Loop i2: 2i2 + 100 + 4i2 + 5(i2- i1) = 0          -5i1 + 11i2 = -100    (2)
From (1) & (2):
i1 = -2
i2 = -10 A

current through 2 resistor = i2          = -10 A
power for 20 resistor = i12R          = (22)(20)          = 80 W