Question
Here is the question, please do your best! "the flywheel of a steam engine runs with a constant angularvelocity of 150 revolutions/min. when steam is shut off, thefriction of the bearings and of the air stops the wheel in2.2h. a) what is the constant angularaccerleration in revolutions per minute squared, of the wheelduring the slow down? b) how many revolutions does the wheel makebefore stopping? c) at the instant the flywheel is turningat 75 rev/min , what is the tangential component of the linearaccerleration of a flywheel particle that is 50 cm from the axis ofrotation? I found parts a and part b. i just don't know how to find part c. according to the posted solution onthis website, the equation to find the tangential componentis A(t) = r where = 1.136 (found in part A) and the r = .50 meters. how do you solve for A(t). I know the answer is supposed to be -9.9 * 10^-4m/s but how do you get that ???? Here is the question, please do your best! "the flywheel of a steam engine runs with a constant angularvelocity of 150 revolutions/min. when steam is shut off, thefriction of the bearings and of the air stops the wheel in2.2h. a) what is the constant angularaccerleration in revolutions per minute squared, of the wheelduring the slow down? b) how many revolutions does the wheel makebefore stopping? c) at the instant the flywheel is turningat 75 rev/min , what is the tangential component of the linearaccerleration of a flywheel particle that is 50 cm from the axis ofrotation? I found parts a and part b. i just don't know how to find part c. according to the posted solution onthis website, the equation to find the tangential componentis A(t) = r where = 1.136 (found in part A) and the r = .50 meters. how do you solve for A(t). I know the answer is supposed to be -9.9 * 10^-4m/s but how do you get that ????
Explanation / Answer
= -1.136 rev/min2 (as you calculated) - ve for deacceleration = -1.136 * 2 /602 (1 rev = 2 rad and 1 min= 60 s) = - 1.98* 10-3 rad/s2 At = r* = -0.50 * 1.98 * 10-3 = -9.9 * 10-4 m/s2 = -9.9 * 10-4 m/s2