Please I need help! PHY2054SUMB18 ackelyn ?Hwk 24 Problem 24.34 8 of 8> For each

Question

Please I need help! PHY2054SUMB18 ackelyn ?Hwk 24 Problem 24.34 8 of 8> For each thin lens shown in, calculate the location of the image of an object that is 13.0 cm to the left of the lens. The lens material has a refractive index of 1.50, and the radii of curvature shown are only the magnitudes. -100 cm 10.0 cmB 100 cm 100 cm 15.0 an Part A Calculate the location of the image to the left of lens (a) Express your answer in centimeters to three significant figures. cIn Submit Part B Calculate the location of the image to the left of lens (b). Express your answer in centimeters to three significant figures. Submit

Explanation / Answer

24.34:

from Lens maker's formula,

1/f = (n - 1)[1 /R1 - 1/R2]

and for lens , 1/f = 1/s + 1/s'

and s = 13 cm

(A) 1/f = (1.50 - 1)[1/10 - 1/(-15)]

f = 12cm

1/12 = 1/13 + 1/s'

s' = 156 cm ........Ans

(B) 1/f = (1.50 - 1)[1/10 - 0]

f = 20 cm

1/20 = 1/13 + 1/s'

s' = - 37.1 cm

(C) 1/f = (1.50 - 1)[1/(-10) - 1/15]

f = -12 cm

1/(-12) = 1/13+ 1/s'

s' = - 6.24 cm

(D) 1/f = (1.50 - 1)[-1/10 + 1/15]

f = - 60 cm

1/(-60) = 1/13 + 1/s'

s' = - 10.7 cm

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