A horizontal force of 750 N is needed toovercome the force of static friction between a level floor and a 250kg crate. What is the acceleration of thecrate if the 750 N force is maintained after the crate begins tomove and the coefficient of kinetic friction is 0.12? A horizontal force of 750 N is needed toovercome the force of static friction between a level floor and a 250kg crate. What is the acceleration of thecrate if the 750 N force is maintained after the crate begins tomove and the coefficient of kinetic friction is 0.12?
Explanation / Answer
Force on movingcrate F = Appliedforce - force due to kineticfriction F = 750 - k* m *g = 750 - 0.12* 250 *9.8 = 456 N Acceleration a = F/m = 456/ 250 = 1.826 m/s2