In the system shown, Block M (15.7 kg) is initially moving tothe left. A force F

Question

In the system shown, Block M (15.7 kg) is initially moving tothe left. A force F, with the magnitude 60.7, acts on itdirected at an angle of 35.0 degrees above the horizontal as shown. The smaller mass, m, is 8.2 kg. There is no friction and thepulley and string are massless.
a. What is the normal force on M? b. What is the tension in the string? c. What is the acceleration of M? d. Is the speed of M increasing or decreasing?
The answers given are a. 119 N b. 69.8 N c. -1.28 d. Increasing
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Explanation / Answer

(a)Apply Newton second law for the mass M in verticledirection                                   Mg = N + F sin                                   N = Mg - F sin                                        =------ Newtons This is the normal force (b) Apply Newtons second law for the mass M inhorizontal direction                          T - F cos = Ma ------------ (1)                                 Apply Newtons law for the mass mthen                                 mg - T = ma       From the above twoequations                  mg - Ma - Fcos = Ma                                         a = (mg - F cos) / (m+M)                                               =------------ m/s2      Substitude this value in equation (1) weget                                 T = Ma + F cos                                     =---------- N   If a is positive then the velocityincreaseing                 

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