A sinusoidal voltage source v =10sin( t ) Volts is connected across a 1 kresisto
ID: 1830058 • Letter: A
Question
A sinusoidal voltage source v =10sin(t) Volts is connected across a 1 kresistor. 1. Make a sketch of p(t), the instantaneous powersupplied by the source. 2. Determine the average power supplied by the source. 3. Now, suppose that a square wave generator is used as thesource. If the square wave signal has a peak-to-peak of 20 Voltsand a zero average value, determine the average power supplied bythe source. 4. Next, if the square wave signal has a peak-to-peak of 20Volts and a 10-Volt average value, determine the average powersupplied by the source. A sinusoidal voltage source v =10sin(t) Volts is connected across a 1 kresistor. 1. Make a sketch of p(t), the instantaneous powersupplied by the source. 2. Determine the average power supplied by the source. 3. Now, suppose that a square wave generator is used as thesource. If the square wave signal has a peak-to-peak of 20 Voltsand a zero average value, determine the average power supplied bythe source. 4. Next, if the square wave signal has a peak-to-peak of 20Volts and a 10-Volt average value, determine the average powersupplied by the source.Explanation / Answer
P is v2/R or 100/1000. .1 watt note: v2 is always 100, doesn't matter if v is 10 or -10
4. P-P is still 20, but averge is 10. So squarewave switches between 0 and 20. When v is 20, power is400/1000 =.4 watts. This is at 50% duty cycle, so average is1/2 of 400, or 200 watts