The figure below shows two points in an E-field: Point 1 is at (Xi,Yi) = (34) in
ID: 1869933 • Letter: T
Question
The figure below shows two points in an E-field: Point 1 is at (Xi,Yi) = (34) in m, and Point 2 is at (X2.Y2)-(129) in m. The Electric Field is constant, with a magnitude of 62 V/m, and is directed parallel to the +X-axis. The potential at point 2 is 642 V. Calculate the potential at poin1 Correct, computer gets: 1.200e+03 v Hint: The lines in the figure are the electric field lines. Draw equipotential lines and caculate the difference in potential. (This involved the E-field which is given, and the (relevant!) distance... which distance matters). How is the potential at point 1 related to the potential at point 2, if you know the change (difference) in potential between them? Think very carefully about signs, which point should be at the higher potential, 1 or 2! 3. [1pt] Calculate the work required for an external force to move a negative charge of Q = 08 microC at constant speed from point 2 to pont l as defined above in problem 2Explanation / Answer
Workdone required for an external source = |Workdone by elctric force|
= q*E*dx
= q*E*(x2-x1)
= 608*10^-6*62*(12 - 3)
= 0.3393 J