Constants Part A Two parallel plates have equal and opposite charges. When the s

Question

Constants Part A Two parallel plates have equal and opposite charges. When the space between the plates is evacuated, the electric field is E 3.50x105 V/m. When the space is filled with dielectric, the electric field is E-2.50x105 V/m . What is the charge density on each surface of the dielectric? You may want to review (Pages 797 For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of C/ Submit Request Answer Part B What is the dielectric constant? Submit uest Ans Provide Feedback

Explanation / Answer

Here

part a)

let the charge density is sigma

electric field = sigma/epsilon_0

3.5 *10^5 = sigma/(8.854 *10^-12)

solving for sigma

sigma = 3.1 *10^-6 C/m^2

the charge density of each surface is 3.1 *10^-6 C/m^2

part b)

dielectric constant = electric field/new electric field

dielectric constant = 3.5 *10^5/(2.5 *10^5)

dielectric constant = 1.4

the dielectric constant is 1.4

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